Substitute the values of a a, d d, and e e into the vertex form a ( x d) 2 e a ( x d) 2 e ( x 0) 2 − 1 ( x 0) 2 1 ( x 0) 2 − 1 ( x 0) 2 1 Set y y equal to the new right side y = ( x 0) 2 − 1 y = ( x 0) 2 1 y = ( x 0) 2 − 1 y = ( x 0) 2 1 xintercepts states that the graph cross the xaxis Substitute the value of y = 0 in 1 to solve for x;Options /x = 41 x21=41 x=41 x=41 Which is the correct translation of the sentence into an equation?

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Graph the equation. y=3(x+1)^2-2
Graph the equation. y=3(x+1)^2-2-Y=4x1 Geometric figure Straight Line Slope = 8000/00 = 4000 xintercept = 1/4 = yintercept = 1/1 = Rearrange Rearrange the equation by subtracting what isEXAMPLE 1 Graphing an Equation by Plotting Points Sketch the graph of y = x^2 Solution Since the given equation clearly shows how values of y are related to values of x, it seems reasonable to start by assigning several different numbers to x and then find the corresponding values of y to get points that lie on the graph




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If the graph of y = f (x) is translated a units horizontally and b units vertically, then the equation of the translated graph is y − b = f(x − a) For in a translation, every point on the graph moves in the same manner Let (x 1, y 1), then, be the coördinates of any point on the graph of y = fGraph the line y = 3 x 1 From the equation, we know that the y intercept is 1 , the point ( 0, 1) and the slope is 3 Graph the point ( 0, 1) and from there go up 3 units and to the right 1 unit and graph a second point Draw the line that contains both points Horizontal and vertical lines have extra simple equationsXintercepts = (3, 0) yintercepts states that the graph cross the yaxis Substitute the value x = 0 in 1 to solve for y;
Try it now y=2x1 Clickable Demo Try entering y=2x1 into the text box After you enter the expression, Algebra Calculator will graph the equation y=2x1 Graph the equation \(y=\frac{2}{3}x1\) This equation is already in SlopeIntercept Form The slope is identified as m equals twothirds m=23 and the yintercept is at the ordered pair, (0, negative 1) (0,1) That is where the graphing begins Plot the first point at the yintercept, then move from that point according to the slopeIn order to graph , we need to plot some points To do that, we need to plug in some x values to get some y values So let's find the first point Start with the given function Plug in Raise 2 to the 2nd power to get 4 Multiply 1 and 4 to get 4 Multiply 3 and 2 to get 6 Add 4 and 6 to get 10
In this math video lesson I show the student how to graph the equation xy=1 This equation is in standard form and I covert that to slope intercept form tFree graphing calculator instantly graphs your math problemsGraph the equation y equals 3 x Let x equals 3 − 2, − 1, 0, 1, 2, and 3 Find the following yvalues Then choose the correct graph of the equation to the right




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Step 1 Take x = 0 and solve for y We will get 0 −y = 1 ⇒ y = − 1 So the first point of our consideration is (0, −1) Step 2 Next we take y = 0 and solve for x We get x −0 = 1 ⇒ x = 1 So the next point in our consideration is (1,0) So finding these 2 points and joining them through a line, we then extend the line on either sides to whatever length we see fitNow, choose an xvalue (besides x=0) and plot the point on the line y = − 3 5 x 1 that corresponds to this value Then, use these two points to graph the line The equation, y = 4 x − 3, is written in slopeintercept form, which is y = m x b, to find, x, the number of small seashells in the collection before the were added?




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Example 1 Sketch the graph of 2x y = 3 Solution We wish to find several pairs of numbers that will make this equation true We will accomplish this by choosing a number for x and then finding a corresponding value for y A table of values is used to record the dataThe slope of a line containing the points P 1 (x 1, y 1) and P 2 (x 2, y 2) is given by Two lines are parallel if they have the same slope (m 1 = m 2) Two lines are perpendicular if the product of their slopes is l(m 1 * m 2 = 1) The pointslope form of a line with slope m and passing through the point (x 1, y 1) is y y 1 m(x x 1) Explanation one way is to find the intercepts, that is where the graph crosses the x and y axes ∙ let x = 0, in the equation for yintercept ∙ let y = 0, in the equation for xintercept x = 0 ⇒ y = 0 − 1 ⇒ y = − 1 ← yintercept y = 0 ⇒ x −1 = 0




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Answer (1 of 10) Start off by understanding the equation Your equation is a linear or straight line equation Now, let's dissect it a bit The 1 is called your yintercept The yintercept of this line is the value of y at the point where the line crosses the y axis Now, look at the 2 only inIn this form, (x 1)^2, I usually set the inside part of the binomial equal to 0 x 1 = 0 When you solve that equation, it gives you the xvalue of the vertex This should be the "middle" value of your list of inputs so that you can be sure to get the symmetry of the graph well displayedLike if you got two oranges for five dollars y= 2 (x/5) where y is oranges and x is the amount of money you had Say you had dollars, the equation would become y=2 (/5) which equals y=2 (4) which equals y=8 , so you could get 8 oranges with dollars That was just a simple example



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Y 4 = 4(x 1) A The graph is a line that goes through the points (1,4) and (0,0) BCheck this out y = \left x 1 \right \left x 2 \right So, equate both the linear expressions with 0 And the resulting value will be the intersection of the equation uAnswer (1 of 8) If x = 1 the numerator (top line) = 0 so y = 0 when x = 1 If x =– 1 the denominator (bottom line) = 0 which means y is infinite and this means there is a vertical asymptote at x = –1 If x is large then y = – 1 (a bit) and this means there is a horizontal asymptote of y = 1 A




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PreAlgebra Graph y=x1 y = x 1 y = x 1 Use the slopeintercept form to find the slope and yintercept Tap for more steps The slopeintercept form is y = m x b y = m x b, where m m is the slope and b b is the yintercept y = m x b y = m x bFunction Grapher is a full featured Graphing Utility that supports graphing up to 5 functions together You can also save your work as a URL (website link) Usage To plot a function just type it into the function box Use "x" as the variable like thisFormula Method 1 The line y = L is called a Horizontal asymptote of the curve y = f (x) if either Method 2 For the rational function, f (x) In equation of Horizontal Asymptotes, 1 If the degree of x in the numerator is less than the degree of x in the denominator then




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Solutions for Chapter P1 Problem 10E Sketch the graph of the equation by point plottingy = x − 1 Get solutions Get solutions Get solutions done loading Looking for the textbook?How do you graph y=x2Video instruction on how to graph the equation y=x2 how do you graph y=x2Video instruction on how to graph the equation y=x2Example 1 Graph the equation of the line 2x4y=8 using its intercepts I hope you recognize that this is an equation of a line in Standard Form where both the x and y variables are found on one side of the equation opposite the constant term It is a common practice in an algebra class to ask students to graph the line using the intercept method when the line is in Standard Form




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Plotting ordered pairs is a very good place to start learning about the graphs of quadratics!Add 1 to both sides we get;Draw the graph of the equation 2 x 3 y = 1 1 Find the value of y when x = 1 from the graph Easy Open in App Solution Verified by Toppr x 4 1 y 1 3 Given that, 2 x 3 y = 1 1 2 3 y = 1 1




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Simplify y = 1 yintercept = (0, 1) Now, using these x and yintercepts points to graph the AnswerBBoth (1,4) and (2,8) are points on the graph athenabug06 athenabug06 Mathematics High School answered Which statement is true about the graph of this equation? 5 ( 4, 5) ( 4, 5) Let's verify the first one and we'll leave the rest to you to verify For the first one we simply plug x = − 2 x = − 2 into the equation and compute y y y = ( − 2 − 1) 2 − 4 = ( − 3) 2 − 4 = 9 − 4 = 5 y = ( − 2 − 1) 2 − 4 = ( − 3) 2 − 4 =



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From this chart, we see that the parabola y = x 2 contains the points (3, 9) and (4, 16) On the other hand, he parabola y = 2x 2 contains the points (3, 18) and (4, 32) On the first equation, y = x 2, to move horizontally across the xaxis from x = 3 to x = 4, we move up vertically on the yaxis from y = 9 to y = 16 which is 7 unitsSo, to go from the point (3, 9) to (4, 16), we move over 1The graph of y ≤ x The graph of y ≥ x Examine the 3 graphs below to understand how linear inqualities relate to a linear equation Below is the graph of the equation of the line y = x 1 The equation of y ≥ x 1 The equation of y ≤ x 1 The graph of y > x 1 The following steps can be used to draw the graph of the given equation Step 1 Write the given equation Step 2 Simplify the above equation Step 3 Draw the graph of (y = x) Step 4 Find the yintercept and the slope of the above equation c = 1




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Example 6 Draw the graph of x y = 7 x y = 7 To draw the graph, we need at least two solutions of the equation Putting x = 0, 0 y = 7 y = 7 So, (0,7) is a solution of the equation Putting y = 0 , x 0 = 7 x = 7 So, (7,0) is a solution of Select all statements that are true about the linear equation y=x1 A coordinate pair on the graph of the equation is a solution to the equation The point (0, −1) lies on the graph of the equation The graph of the equation is the set of points that are solutions to the equation The point (1, 2) lies on the graph of the equationAnswer (1 of 2) The graphs consisting modulus function and linear equations are the simplest ones Wondering How?



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Graph the following equation y=2x1 How to Graph the Equation in Algebra Calculator First go to the Algebra Calculator main page Type the following y=2x1;Four less than a number is 12 options n12=4 n4=12 4n=12 12n=4To find the x x coordinate of the vertex, set the inside of the absolute value x − 1 x 1 equal to 0 0 In this case, x − 1 = 0 x 1 = 0 x − 1 = 0 x 1 = 0 Add 1 1 to both sides of the equation x = 1 x = 1 Replace the variable x x with 1 1 in the expression y = ( 1) − 1 y = ( 1) 1




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Y = x− 1 y = x 1 Use the slopeintercept form to find the slope and yintercept Tap for more steps Find the values of m m and b b using the form y = m x b y = m x b m = 1 m = 1 b = − 1 b = 1 The slope of the line is the value of m m, and the yintercept is the value of b b Slope 1 1Multiply both sides by 3 we get;For x = 1, y = 1, therefore (1,1) satisfies the linear equation y = x For x = 4, y = 4, therefore (4, 4) satisfies the linear equation y = x By plotting the points (1,1) and (4, 4) on the graph paper and joining them by a line, we obtain the graph of y = x The given equation is y = – x To draw the graph of this equation, we need at least




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Using the graph of f(x) = log10x below, approximate the value of y in the equation 10y = 4 log base 10 graph y ≈ −1 y ≈ 060 y ≈ 001 y ≈ 148Graph y = 2x 1Graphing a line requires two points of the line which can be obtained by finding the yintercept and slope




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